Using atoi to fill an array of ints

Question

First time asking a question on here. Apologies if there's already threads about this but i had a few searches and didn't quite find what i think i was looking for. I'm very new to C and am working through a few homework exercises for my microcontroller systems class. We're currently working through easy exercises before we get into embedded C and I'm trying to write a program that'll take a line of text consisting of 10 numbers separated by commas and fill an array of ints with it. As a hint we were told to use a substring and atoi. I think i'm close to getting it right but i can't get it to output my numbers properly.

Also i'm not looking spoon fed answers. A few hints would suffice for now. I'd like to try figuring it out myself before asking for the solution.

Here is my code:

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    int a[10];
    char str[] = {1,2,3,4,5,6,7,8,9,10}; //contains string of numbers
    int i;
    puts("This prints out ten numbers:");

    for (i = 0; i < 10; i++)
    {
        a[i] = atoi(str);
        printf("%d", a[i]);
            //i'm guessing the problem lies in one of the above two lines
    }
    return 0;
}

This is outputting the following:

This prints out ten numbers:
0000000000

Thanks to anyone that can help! Chris

Answer 1

You said that you have to use a line of text separated by commas but you've actually declared a char array containing ten (binary) integers. To get that into a string you just need to do this:

char str[] = "1,2,3,4,5,6,7,8,9,10";

Then you'll need someway to process this string to get each number out and into your array of int.