I need to do this:
if [ $X != "dogs" and "birds" and "dogs" ]
then
echo "it's is a monkey"
fi
with bash script. How to proceed?
You need to turn each option into a separate conditional expression, and then join them together with the && (AND) operator.
if [[ $X != dogs && $X != birds && $X != cats ]]; then
echo "'$X' is not dogs or birds or cats. It must be monkeys."
fi
You can also do this with single [...], but then you have to quote the parameter expansions, use a separate set of brackets for each comparison, and put the &&s outside them:
if [ "$X" != dogs ] && [ "$X" != birds ] && [ "$X" != cats ]; then
Note that you don't need double-quotes around single-word literal strings like dogs, but you do need them around parameter expansions (variables) like $X inside the single-bracket version, because otherwise a space in the value of the parameter will cause a syntax error.
The shell operator version of OR is ||, which works the same way.
As a side note, it's better stylistically to use lowercase for regular variable names in shell scripts; all-caps names are best reserved for variables that come in from the environment, like $PATH and $TERM and so on. I'd use a more meaningful name like $animal here, but eve if I went with a generic $x, I wouldn't capitalize it.