Do unimplement partial methods get replaced with null when used as a delegate parameter?

Question

So i have 2 distinct methods.

one is a normal method

void DoSomething(delegate x)
{
     foreach(......)
     { x(); }
}

the other is a partial but unimplemented one

partial void DoWorkInForEach();

when i call my first method like this

DoSomething(DoWorkInForEach);

what will happen, will the delegate parameter be null, will my entire method call be deleted?

Answer 1

From the language specification:

10.2.7 Partial methods

[...]

If a defining declaration but not an implementing declaration is given for a partial method M, the following restrictions apply:

• It is a compile-time error to create a delegate to method (§7.6.10.5).

• It is a compile-time error to refer to M inside an anonymous function that is converted to an expression tree type (§6.5.2).

• Expressions occurring as part of an invocation of M do not affect the definite assignment state (§5.3), which can potentially lead to compile-time errors.

• M cannot be the entry point for an application (§3.1).

If required, you can use a lambda here instead of a method-group, which would essentially give you a no-op delegate:

DoSomething(() => DoWorkInForEach());