I want to convert date strVal="1992-12-12" or "1992-9-9" of the form to 19921212 & 19920909. For doing so I have written following piece of code in C/C++. But the trouble is it converts 1992-12-12 to 1992012012. Can anyone guide me as to how show i fix this bug? I may also have inputs of the form "1992-9" and I would like to convert it to 19920900. Or "1992" to "19920000"
stringstream collectTimeBegin;
for (string::iterator it = strVal.begin(); it != strVal.end(); )
{
if (*it != '-')
{
cout<< "\n -- *it=" << *it;
collectTimeBegin << *it;
it++;
}
else
{
stringstream si("");
stringstream sj("");
int i;
it++;
si << *(it + 1);
sj<< *(it + 2);
i = atoi((si.str()).c_str()), j = atoi((sj.str()).c_str());
cout << "\n i=" << i << "\t j=" << j << "\n";
if ((i == 4) || (i == 5) || (i == 6) || (i == 7) || (i == 8) || (i == 9))
{
cout << "\n 1. *it=" << *it;
collectTimeBegin << *it;
it++;
}
else if ((j == 0) || (j == 1) || (j == 2) || (j == 3) || (j == 4) ||
(j == 5) || (j == 6) || (j == 7) || (j == 8) || (j == 9))
{
string str = "0";
cout << "\n 2. *it=" << *it;
collectTimeBegin << str;
collectTimeBegin << *it;
it++;
}
}
}
Here's a solution using standard C++; it uses the same approach as Christian's: split the input based on the dashes, pad missing digits with 0s:
#include <string>
#include <sstream>
#include <algorithm>
int main()
{
std::string date = "1992-9-12";
std::replace(date.begin(), date.end(), '-', ' '); // "1992 9 12"
std::istringstream iss(date);
int year = 0, month = 0, day = 0;
if (iss.good()) iss >> year; // 1992
if (iss.good()) iss >> month; // 9
if (iss.good()) iss >> day; // 12
std::ostringstream oss;
oss.fill('0');
oss.width(4); oss << year;
oss.width(2); oss << month;
oss.width(2); oss << day;
std::string convertedDate = oss.str(); // 19920912
}