Passing file path argument to a CherryPy

Question

In CherryPy how do you pass an argument like file path (i.e. /abc/def/ghi) through a URL? I want to do something like http://...../filepath="abc/def/ghi". Thanks.

Answer 1

What about using ~ as a delimiter and then just replace ~ in the string with /...

http://...../filepath=abc~def~ghi

def SomePage(self, filepath=None):
    filepath.replace('~', '/')
    return 'HelloWorld'

Hope this helps,

Andrew