Code calls terminate instead of throwing exception

Question

I want to throw an exception like this:

if (...) {  
    throw "not found";  
}

and catch it like this:

try {  
    myfunction();  
} catch (const char * msg) {  
    cout << msg << endl;  
}

but then it says

terminate called after throwing an instance of 'char const*'

Why does it call terminate and not throw my "not found"?

EDIT:

I changed it to this:

try {
    throw "not found";
} catch (const char * msg) {
    cout << "test" << endl;
} catch(...) {
    cout << "test" << endl;
}

and I get the same error!

EDIT2: When I don't call a specific method above, it works! But I don't understand what this method has to do with exceptions, I didn't use it in any other function than the above mentioned myfunction(). Let me test some more and then I will get back to you!

EDIT3:

Oh my, this is embarrassing. Looks like I called the wrong function. I am so so sorry to have bothered you with this shameful experience!

Answer 1

If you use throw outside of a try/catch block, terminate gets called. Make sure the function that throws is in the try block.

#include <iostream>

void myFunc()
{
    throw "Throwing!";
}

int main()
{
    try
    {
        myFunc();
    }
    catch(...)
    {
        std::cout << "Works fine.";
    }

    myFunc(); // Terminate gets called.

    return 0;

}