smallest value of array

Question

I'm trying to write a function that will return the smallest value of an array. So far I have this, but all it returns is 0.

I don't see how it would return 0 since I am using a for loop to cycle through the array. Perhaps it is not cycling through the arrays values as I would think it does. Can anyone elaborate on the logic and the fallacy in this code?

#include <iostream>

using namespace std;

int newArray[9] = {4,5,9,3,6,2,1,7,8};


int minArray()
{
    int index = 1;
    int minimum;

    for (int i = 0; i < 9; i++)
    {
        if (newArray[i] > newArray[index])
        {
            minimum = newArray[index];
        }
        index++;

    }

    return minimum;
}


int main()    
{   
    cout << "original array:\n ";
    for (int i = 0; i < 9; i++)
    {
        cout << newArray[i] << ", ";
    }

    cout << "minimum value of array: ";
    cout << minArray();

    return 0;
}

Answer 1

A good idea might be to initialize minimum with an element in the array. So:

minimum = newArray[0]

In your loop (pseudocode assuming you don't want the answer):

if: newArray[pos] < minimum

        minimum = newArray[pos];