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cunixoperating-system

How can I check whether a memory address is writable or not at runtime?


How can I check whether a memory address is writable or not at runtime?

For example, I want to implement is_writable_address in following code. Is it possible?

#include <stdio.h>

int is_writable_address(void *p) {
    // TODO
}

void func(char *s) {
    if (is_writable_address(s)) {
        *s = 'x';
    }
}

int main() {
    char *s1 = "foo";
    char s2[] = "bar";

    func(s1);
    func(s2);
    printf("%s, %s\n", s1, s2);
    return 0;
}

Solution

  • I generally concur with those suggesting that this is a bad idea.

    That said, and given that the question has the UNIX tag, the classic way to do this on UNIX-like operating systems is to use a read() from /dev/zero:

    #include <fcntl.h>
    #include <unistd.h>
    
    int is_writeable(void *p)
    {
        int fd = open("/dev/zero", O_RDONLY);
        int writeable;
    
        if (fd < 0)
            return -1; /* Should not happen */
    
        writeable = read(fd, p, 1) == 1;
        close(fd);
    
        return writeable;
    }