Consider this XML snippet with "nodes" which can have unlimited child levels of "subnode" elements.
I want to find @type
attribute of the node
for any given subnode
, based on its @id
attribute. For example, if I have an id of 9 then I want to return the type="foo" from above.
<xml>
<node type="bar">
<subnode id="4">
<subnode id="5"/>
</subnode>
<subnode id="6"/>
</node>
<node type="foo">
<subnode id="7">
<subnode id="8">
<subnode id="9"/>
</subnode>
</subnode>
<subnode id="10"/>
</node>
</xml>
The E4X I have come up with, but which fails is:
xml.node.(subnode.(@id == '8')).@type
I can kind of see why it doesn't work. What would make more sense is the following but the syntax fails (in AS3):
xml.node.(..subnode.(@id == '8')).@type
How can this be done?
You should be able to get the type value using this E4X:
xml.node.(descendants("subnode").@id.contains("8")).@type;