How to convert a function that returns a int to a function that returns a bool using boost::bind?

Question

I have something like the following:

 struct A{
  virtual int derp(){ 
      if(herp()) return 1; 
      else return 0; 
   }
  void slurp(){
    boost::function<bool(int x, int y)> purp = /** boost bind derp to match lvalue sig  **/;
  }
 }

Any ideas? I want to create the function prup which basically calls derp and ignores the (x,y) passed in.

I need something like

bool purp(int x, int y){ return derp(); }

but want to avoid creating it as a member function, and rather just create it locally if possible?

Answer 1

If C++11 is available, consider using a lambda. Otherwise, you can use Boost.Lambda:

boost::function<bool(int x, int y)> purp = !!boost::lambda::bind(&A::derp, this);

That uses the standard conversion of int to bool.

If you want a specific return value of A::derp to be true, then use ==. For example, suppose you want a return value of 3 to be true:

boost::function<bool(int x, int y)> purp = boost::lambda::bind(&A::derp, this) == 3;

EDIT: Complete example:

#include <iostream>

#include <boost/function.hpp>
#include <boost/lambda/lambda.hpp>
#include <boost/lambda/bind.hpp>

struct A {
    virtual int derp() {
        std::cout << "within A::derp()\n";
        return 0;
    }
    void slurp() {
        boost::function<bool(int x, int y)> purp = !!boost::lambda::bind(&A::derp, this);
        std::cout << (purp(3, 14) ? "true" : "false") << '\n';
    }
};

int main()
{
    A a;
    a.slurp();
}

Outputs:

within A::derp()
false