How do I fill a va_list

Question

If I have a va_list I know how to extract all its elements:

void printInts(int n,...)
{
    va_list va;
    va_start(va, n);
    for(unsigned int i=0; i<n; i++)
    {
        int arg=va_arg(va, int);
        printf("%d",arg);
    }
    va_end(va);
} 

So when I call printInts(3,1,2,3) the va_list get filled of all the parameters.
But how do I manually fill a va_list without using va_start? I mean that I want something like:

va_list va;
push_arg(va, int, 5); // And so on until I fill all parameters
...

I need this because there is a function that accept a va_list as argument, and I don't know how to fill that va_list of all its parameters.

Answer 1

There's no ability to fill a va_list explicitly.

You should write a wrapper function. Say you need to call your function foo, instead of manually filling in a va_list, you define a new function like so:

void call_foo(int arg1, ...)
{
   va_list ap;
   va_start(ap, arg1);
   foo(arg1, ap);
   va_end(ap);
}

Now you can call foo, which takes a va_list, however you like, by doing e.g. call_foo(1,2,3,4);, call_foo(1, 1, "Hello"); etc.

This will only allow you to specify the arguments at compile time, you can't build the arguments at runtime.