Glob-like brace Wildcards in Bash

Question

Lets say I've a directory /etc/php5/conf.d/, with the following hypothetical files in it:

mysql.ini
mysqli.ini
20-mysql.ini
20-mysqli.ini
20-pdo_mysql.ini

I would like to delete all these files except the last one (pdo), this is what I have at the moment:

for phpIni in mysql mysqli; do
    if [[ -f /etc/php5/conf.d/$phpIni.ini ]]; then
        rm /etc/php5/conf.d/$phpIni.ini
    if [[ -f /etc/php5/conf.d/20-$phpIni.ini ]]; then
        rm /etc/php5/conf.d/20-$phpIni.ini
    fi
done

It works, but I can't help noticing that the above could be simplified with glob patterns, such as:

if [[ ! -z /etc/php5/conf.d/{,20-}mysql*ini ]]; then
    rm /etc/php5/conf.d/{,20-}mysql*ini
fi

There's a problem though, if the any of the expansions doesn't exists, rm will complain about it:

$ if [[ ! -z /etc/php5/conf.d/{,20-}mysql*ini ]]; then rm /etc/php5/conf.d/{,20-}mysql*ini; fi
rm: cannot remove `/etc/php5/conf.d/20-mysql*ini': No such file or directory

How can I make rm only remove existing files? Or at least prevent it from throwing all these errors?

Answer 1

You can use rm -f, it will not complain if files don't exist: as seen in the man page, "ignore nonexistent files, never prompt".