matlab image smoothing with conv2

Question

I am a newbie to imaging processing and I found some difficulties in implementing image smoothing.

Basically, I have an image A and I would like to replace everything pixel by its local average. So I define masks M1 = ones(10) and use

 newImage = conv2(A, M1,'same')

It works fine. But in image A, there are meaningless pixels fully due to noise and I don't want to include them in the averaging. How do I do that, say the meaningful pixels are defined via another mask M2?

I made a simple loop over the image. It works but is way slower than the conv2().

for i = 1:self.row
    for j = 1:self.col
        if self.M2(i,j) % only treat meaningful pixels
            A(i,j) = self.createAvgPhasor(i,j);
        end
    end
end

    function [s_avg]=createAvgPhasor(self,m,n)
        % bound box along x 
        if m > self.rB
            xl = m - self.rB;
        else
            xl = 1;
        end
        if m < self.row_rB
            xu = m + self.rB;
        else
            xu = self.row;
        end
        % bound box along y 
        if n > self.rB
            yl = n - self.rB;
        else
            yl = 1;
        end
        if n < self.col_rB
            yu = n + self.rB;
        else
            yu = self.col;
        end
        M1 = false(self.row,self.col);
        M1(xl:xu,yl:yu) = true;
        msk = M1 & self.M2;
        s_avg = mean(self.Phi(msk));
    end

Thanks very much for your help.

Answer 1

Excluding the bad points from the convolution is easy. If M2 contains a 1 for pixels that you want to include, and a 0 for those that you don't, then you just do this:

newImage = conv2(A.*M2, M1,'same');

This might be sufficient for your purposes, but you have to decide exactly what you mean by 'averaging". For example, given your kernal ones(10), at the end you may want to do something like this:

npts = conv2(ones(size(A)).*M2, M1, 'same')
newImage = newImage./npts

I.e., divide each pixel by the number of pixels that were actually included in in the convolution for that pixel.

Actually, the above might also do the right thing even if you weighted different points differently. But it really depends on exactly what you want to do.