example: i need the numbers of which the sum of the amount where id = 1 is not equal of the sum of the amount where id <> 1, together with the id's and difference.
The table (view in this case) may look like this:
NUMBER AMOUNT ID
0001 500 1
0001 500 2
0002 400 3
0003 299 1
0003 300 3
0003 300 3
Many thanks for your help on this one.
Using this query you can get sum of amounts grouped by number, with ID equals 1 and ID not equals 1.
SELECT NUMBER
, SUM(CASE WHEN ID = 1 THEN AMOUNT ELSE 0 END) AS Equals1
, SUM(CASE WHEN ID <> 1 THEN AMOUNT ELSE 0 END) AS NotEquals1
FROM DataTable
GROUP BY NUMBER
If this is you expected, use following query to get difference amounts grouped by number.
SELECT NUMBER, (Equals1 - NotEquals1) AS DifferenceAmount
FROM
(
SELECT NUMBER
, SUM(CASE WHEN ID = 1 THEN AMOUNT ELSE 0 END) AS Equals1
, SUM(CASE WHEN ID <> 1 THEN AMOUNT ELSE 0 END) AS NotEquals1
FROM DataTable
GROUP BY NUMBER
) AS GroupedTable
WHERE Equals1 <> NotEquals1