Is there a more concise and time efficient way to achieve the following zip operation in Python? I am pairing lists of lists together to make new lists, as follows:
>>> a
[[1, 2, 3], [4, 5, 6]]
>>> b
[[10, 11, 12], [13, 14, 15]]
>>> for x, y in zip(a, b):
... print zip(*[x, y])
...
[(1, 10), (2, 11), (3, 12)]
[(4, 13), (5, 14), (6, 15)]
thanks.
I don't really see a better way other than replacing:
print zip(*[x, y])
with:
print zip(x,y)
If you're really working with 2 element lists, you could probably just do:
print zip( a[0], b[0] )
print zip( a[1], b[1] )
(It'll be slightly more efficient as you leave off 1 zip, but I'm not convinced that it is more clear, which is what you should really be worried about).
If you're really into compact code, you can use map:
map(zip,a,b) #[[(1, 10), (2, 11), (3, 12)], [(4, 13), (5, 14), (6, 15)]]
Which again might be more efficient than the other version, but I think you pay a slight price in code clarity (though others may disagree).