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mathbinaryexponentexponential

How to determine 2^x = 64

I know the answer to this question is 6... but I am wondering what the formula is to figure this out.

I will always need to solve for x in this scenario.

TIA

Solution

  • log(64) / log(2) = x. Or in more general terms, if y^x = z, then x = log(z) / log(y)