I have created a linked list struct in c
struct node{
int value;
struct node* next;
};
a method to add a node at the start of the list :
void addFirst(struct node *list, int value){
struct node *new_node = (struct node*) malloc (sizeof (struct node));
new_node->value = value;
new_node->next = list;
list = new_node;
}
I create a list (malloc and everything), then call this method, it adds the new node inside the method but when i get back to my main my old list remains unchanged. Using DDD debugger to check everything. How is this possible? I am not able to change the method signature so it has to be done like this.
If you really need to do it this way, you have to re-cast the pointer. Something like this:
struct node *my_list = null;
addFirst((struct node *)&my_list, 123);
void addFirst(struct node *list, int value){
struct node **real_list = (struct node **)list;
struct node *new_node = (struct node*) malloc (sizeof (struct node));
new_node->value = value;
new_node->next = *real_list;
*real_list = new_node;
}