How to use a range of numbers as a case statement in Bash?

Question

I am trying to do the following using case in Bash (in Linux).

If X is between 460 and 660, output X information.

If X is between 661 and 800, do something else.

Etc.

Right now this is what I have:

case $MovieRes in
    [461-660]*) echo "$MovieName,480p" >> moviefinal ;;
    [661-890]*) echo "$MovieName,720p" >> moviefinal ;;
    [891-1200]*) echo "$MovieName,1080p" >> moviefinal ;;
    *) echo "$MovieName,DVD" >> moviefinal ;;
esac

But somehow many of the ones that are 480p, 720p or 1080p are ending with DVD instead. The variable $MovieRes is a simple list that shows, for each line, a number between 1 and 1200. Depending on the value, case decides which "case" to apply.

I would like to know how to actually use case to accomplish this since it is a bit confusing when dealing with ranges like this.

Answer 1

In bash, you can use the arithmetic expression: ((...))

if ((461<=X && X<=660))
then
    echo "480p"
elif ((661<=X && X<=890))
then
    echo "720p"
elif ((891<=X && X<=1200))
then
    echo "1080p"
else
    echo "DVD"
fi >> moviefinal