Adding Arrays of Digits as if They Represented Numbers

Question

I have the following problem. Suppose I have to arrays X and Y whose entries consist of integers in the range 0 through 9 like

X = [1 2 3]
Y = [7 0 9]

I want to think of these arrays as being the digits of base-10 numbers, so X represents the number 123 and Y represents the number 709. I want to write a program which outputs the digits of the sum of these integers. So in the example given, it should output the array

Z = [8 3 2]

since 123 + 709 = 832. For the sake of this question it suffices to assume that X and Y have the same length, i.e., that the numbers they represent have the same number of digits. While I am doing this, I also want to keep track of carries which were performed during the addition. So in the example, I'd also want to output

C = [0 0 1]

which represents that I had to carry a 1 when I added the digits 9 + 3 = 12, but that the additions of the digits in other positions went through without carries. So my main question is

• Does anyone know of a simple way to achieve this goal using MATLAB?

So far, what I've come up with is the following code which is given the two numbers as X and Y

clear all; clc;

C = zeros(1, length(X));
for j=length(X):-1:1
    if X(j) + Y(j) > 9
        C(j) = 1;
    end
    Z(j) = mod(X(j) + Y(j), 10);
    if j < length(X)
        if Z(j)  + C(j+1) < 9
            Z(j) = Z(j)  + C(j+1);
        else
            Z(j) = mod(Z(j) + C(j+1), 10);
            C(j) = 1;
        end
    end
end

if C(1) == 1
    Z = [1 Z];
end

Z
C

The problem is that the code only works sometimes. For example, it has no problem working through the example I gave above, that 123 + 709 = 832 with a "carry array" of [0 0 1]. But the input X = 52514 and Y = 41525 does not yield the correct results. So my follow up question is

• Does anyone see the bug in the code above/how can I fix it?

Answer 1

You need to change the line

if Z(j)  + C(j+1) < 9

to

if Z(j)  + C(j+1) <= 9

Then it should work.