In exploring an alternative answer to sarathi's current file line number question, I wrote this one-liner with the expectation that it would print the first line of all files provided:
$ perl -ne 'print "$ARGV : $_" if __LINE__ == 1;' *txt
This did not work as expected; all lines were printed.
Running the one-liner through -MO=Deparse
shows that the conditional is not present. I assume this is because it has been constant-folded at compile time:
$ perl -MO=Deparse -ne 'print "$ARGV : $_" if __LINE__ == 1;' *txt
LINE: while (defined($_ = <ARGV>)) {
print "$ARGV : $_";
}
-e syntax OK
But why?
Run under Perl 5.8.8.
__LINE__
corresponds to the line number in the Perl source, not in the input file.