Getting Empty variable in curl using php

Question

I am trying to execute a url using Curl and i am getting empty output.

However, if we copy-paste Same url in Browser, we are getting value

http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20%28%22YHOO%22,%22AAPL%22,%22GOOG%22,%22MSFT%22%29&env=http://datatables.org/alltables.env&format=json

However, when i try same to get value in php using Curl, i am getting Null

php code

 <?php

$BASE_URL = "http://query.yahooapis.com/v1/public/yql"; 



    // Form YQL query and build URI to YQL Web service
    $yql_query = 'select * from yahoo.finance.quotes where symbol in ("YHOO","AAPL","GOOG","MSFT")&env=http://datatables.org/alltables.env';
    $yql_query_url = $BASE_URL . "?q=" .$yql_query. "&format=json";


    // Make call with cURL
    $session = curl_init($yql_query_url);
    curl_setopt($session, CURLOPT_RETURNTRANSFER,true);
    $json = curl_exec($session);


    echo "<pre>";
    print_r($json);exit;

?>

Any suggestion ??????

Answer 1

Following code is working for me

<?php

$BASE_URL = "http://query.yahooapis.com/v1/public/yql"; 
    $query = 'select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20%28"YHOO","AAPL","GOOG","MSFT"%29&env=http://datatables.org/alltables.env&format=json';
    echo $yql_query_url = $BASE_URL . "?q=" .$query;


    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL,$yql_query_url);
    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

    $content = curl_exec ($ch);
    curl_close ($ch);
    print_r($content);
?>

Query must be properly encoded .

Check it