Got the following simple query which works fine through phpmyadmin but when I add it to my php website no results are returned and no error/warning messages either. If I remove "SET @N=-1;" then it works fine.
<?php
$db_connect = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD, true);
mysql_select_db(DB_NAME, $db_connect);
$test_query = mysql_query("SET @N=-1;SELECT `id`, (@N:=@N+1) AS `mycount` FROM `mydb`;");
for ($i = 0; $i <= mysql_num_rows($test_query)-1; $i++) {
echo mysql_result($db_directorymap, $i, 0) . " " . mysql_result($db_directorymap, $i, 1) . "<br />";
}
?>
UPDATE: I just moved to mysqli but of course I'm still having a problem with the mysql statement and mysqli_multi_query. It seems when it runs the first part of the query the results returned are empty thus a boolean error is given. I'm guessing I have to skip the first set of results but I don't know how to do that?
It's because the mysql_query
function will only accept one query, but you've given it two, separated by a semicolon. Try either:
Running each query separately (don't know if this will work):
mysql_query( "SET @N=-1" );
mysql_query( "SELECT `id`, (@N:=@N+1) AS `mycount` FROM `mydb`" );
Using mysqli with the multi_query function (or a PDO equivalent if there is one).
To answer your updated question: check the PHP manual page for multi_query. I think you'll want to use mysqli::next_result
. Something like this, using procedural style:
mysqli_multi_query($link, $query);
mysqli_next_result($link);
if ($result = mysqli_store_result($link)) {
while ($row = mysqli_fetch_row($result)) {
printf("%s\n", $row[0]);
}
mysqli_free_result($result);
}