Search code examples
matlabanonymous-functionnumerical-integrationdimension-reduction

Matlab: one-dim integral for a function @(x,y,z)

Lets say

 y=2;
 z=4;
 f=@(x,y,z) x.^2+y.^2+z.^2;

And I want to integrate f for x in [0,1]. It seems like I have to define g and do quad(g,0,1)

 g=@(x) f(x,y,z); 
 quad(g,0,1)

The question I have is whether it is possible to do quad on f directly without defining a new function.

Solution

  • Yes ; you can use the anonymous function directly as an argument.

    quad(@(x)f(x,y,z),0,1);