How can I get the file name of the function that is passed to my decorator in python?

Question

I want to get the original file/scriptname, etc of the function that is being decorated. How can I do that?

   def decorate(fn):
        def wrapped():
            return "scriptname: " + fn.scriptname?  
        return wrapped

I tried using fn.__code__ but that gave me more stuff that I needed. I could parse that string to get the function name, but was wondering if there is a more elegant way to do it

Answer 1

Try this:

return "filename: " + fn.func_code.co_filename