This should be quite simple, but for some reason it does not work. Can you point to something?
if ( !empty( $data[$i][19] )) {
$an_image = "<img src='/images/camera.gif' title='Der er et billede' />";
} elseif( !empty( $data[$i][24] )) {
$an_image = "<img src='/images/camera.gif' title='Der er et billede' />";
} elseif( !empty( $data[$i][25] )) {
$an_image = "<img src='/images/camera.gif' title='Der er et billede' />";
} else {
$an_image = "";
}
It should simply check three variables from data, and return an icon if there is something in any of them.
Can you simply use the or operator?
if ( $x || $y || $z ){
$an_image = "<img src='/images/camera.gif' title='Der er et billede' />";
} else {
$an_image = "";
}