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phpprogramming-languagesweak-typing

PHP concatenation of strings and arithmetic operations

I started learning PHP not too long ago and I ran into this issue:

<?php

$a = 1;
$b = 2;

echo "$a * $b  = " . $a * $b;
echo "<br />";

echo "$a / $b  = " . $a / $b;
echo "<br />";

echo "$a + $b  = " . $a + $b;
echo "<br />";

echo "$a - $b  = " . $a - $b;
echo "<br />";

I get the following output:

1 * 2 = 2
1 / 2 = 0.5
3
-1

The last two lines in the output are not what I would expect.

Why is this? How are these expressions evaluated? I'm trying to get a better understanding of the language.

Solution

  • This is happening because the concatenation operator has a higher precedence than the addition or subtraction operators, but multiplication and division have a higher precedence then concatenation.

    So, what you're really executing is this:

    echo ("$a + $b  = " . $a) + $b;
echo ("$a - $b  = " . $a) - $b;

    In the first case, that gets turned into this:

    "1 + 2 = 1" + $b

    Which PHP tries to convert "1 + 2 = 1" into a number (because of type juggling) and gets 1, turning the expression into:

    1 + 2

    Which is why you get 3. The same logic can be applied to the subtraction condition.

    Instead, if you put parenthesis around the calculations, you'll get the desired output.

    echo "$a + $b  = " . ($a + $b);
echo "$a - $b  = " . ($a - $b);