How to show the first N elements of a block and hide the others in css?

Question

I am trying to hide the first 3 elements having the class .row inside the block .container.

What I'm doing is hiding all the .row first, and then I am trying to display the first 3 .row by using .row:nth-child(-n+3)

jsfiddle here: http://jsfiddle.net/z8fMr/1/

.row {
  display: none;
}

.row:nth-child(-n+3) {
  display: block;
}

<div class="content">

  <div class="notarow">I'm not a row and I must remain visible</div>
  <div class="row">Row 1</div>
  <div class="row">Row 2</div>
  <div class="row">Row 3</div>
  <div class="row">Row 4</div>
  <div class="row">Row 5</div>
  <div class="row">Row 6</div>

</div>

I have two problems here:

1. Row 3 is not displayed; am I using nth-child in the wrong way?
2. Is there a better practice than hiding everything and then creating a specific rule to display the n first elements that I want? Is there a way in CSS to just display the first 3 .row and then hide all the other .row?

Answer 1

1. You have a .notarow as the first child, so you have to account for that in your :nth-child() formula. Because of that .notarow, your first .row becomes the second child overall of the parent, so you have to count starting from the second to the fourth:

    .row:nth-child(-n+4) {
        display: block;
    }
   

   Updated fiddle

   .row {
       display: none;
   }
   
   .row:nth-child(-n+4) {
       display: block;
   }

   <div class="content">
       <div class="notarow">I'm not a row and I must remain visible</div>
       <div class="row">Row 1</div>
       <div class="row">Row 2</div>
       <div class="row">Row 3</div>
       <div class="row">Row 4</div>
       <div class="row">Row 5</div>
       <div class="row">Row 6</div>
   </div>

2. What you're doing is fine.