I've created the mysql user function using the levenshtein distance and ratio source codes. I am comparing 2 records and based on a 75% match I want to select the record.
paypal_ipn_orders
with an ITEM
titleitemkey
to find a 75% match in a record called ITEM
as wellitemkey
to table paypal_ipn_orders
Here is the query
UPDATE paypal_ipn_orders
SET sort_num = (SELECT sort_id
FROM itemkey
WHERE levenshtein_ratio(itemkey.item, paypal_ipn_orders.item_name) > 75)
WHERE packing_slip_printed = 0
AND LOWER(payment_status) = 'completed'
AND address_name <> ''
AND shipping < 100
I have adjusted this a few times but it's failing between line 4 and 5 at the levenshtein_ratio part. If it works it says that the subquery returns more than one row. I don't know how to fix it to make it return the correct result, I just lost as to how to make this work.
A subquery on a SET should only return one value. If itemkey has more than one item that is 75% of item_name what do you want to do? The below will use one of the best matches:
UPDATE paypal_ipn_orders
SET sort_num = (SELECT sort_id
FROM itemkey
WHERE levenshtein_ratio(itemkey.item, paypal_ipn_orders.item_name) > 75
ORDER BY levenshtein_ratio(itemkey.item, paypal_ipn_orders.item_name) DESC
LIMIT 1)
WHERE packing_slip_printed = 0
AND LOWER(payment_status) = 'completed'
AND address_name <> ''
AND shipping < 100