Given a global vector list
of ASCII codes and corresponding number values and a string, like 000.00-000.0.0.0
, this function takes an input
token strings 2-char or 3-char long and replaces it with a single ASCII symbol that represents the number value between 0 and 184, then returns the shortened string without deliminator as out
. Also, in reverse (direction 1) given the ASCII symbol it converts back to the number string and returns.
//looks for input string in vector and returns output, 'c' is check row, 'r' is return row
string vectorSearch(string &check, int n, int c, int r)
{
if (check.length() <= 1)
return check;
if (list[n][c] == check || list[n][c] == ('0'+check)) //adds leading zero if 2char long
return list[n][r];
else
return vectorSearch (check, ++n, c, r);
}
//this function takes an ontology and either changes from single char
//to string or takes strings and converts to char representation
string Lexicon::convertOntology(string input, int direction, string out, string temp)
{
if (input == "" && temp == "")
return out; //check for completed conversion
else {
if (input[0] == '.' || input[0] == '-' || input == "") { //found deliniator or endk
if (input != "") return convertOntology(input.substr(1),direction,
out+=vectorSearch(temp, 0, direction, 1-direction), "");
else return convertOntology("", direction,
out+=vectorSearch(temp, 0, direction, 1-direction), "");
} else
return convertOntology(input.substr(1), direction, out, temp+=input[0]); //increment and check
}
}
These functions work fine except for on output after the last char is parsed. With a break on the line return convertOntology(input.substr(1), direction, out+=add, temp);
there is an error when input == ""
and temp == "0"
- the last pass through vectorSearch()
should clear the temp and add the temp char to the out string, since the temp is == 1char then it should be returned from vectorSearch()
as it is. Then clear the convertOntology()
return check of input
and temp == ""
. But, it never reaches a break on the first line of vectorSearch()
and there is an
Unhandled exception at 0x77bc15de exception: std::out_of_range at memory location 0x0035cf1c
What is going on? Is this an issue with recursion backtracking through returns and I am missing a return somewhere to break the recursion loop?
for the case where temp == ""
and input != ""
you call input.substr(1)
which is, well, out of range.