How to store int in char * in iphone

Question

Can anyone help converting the Int to char array as i have buffer as

char *buffer = NULL;  
int lengthOfComponent = -1;   
char *obj;
buffer[index]= (char *)&lengthOfComponent; 

if i do this it is thorwing EXCESS BAD ACCESS after the execution how to store the value of the obj to buffer using memcpy

Answer 1

Of course you cannot write in buffer[index], it is not allocated!

buffer = malloc(sizeof(char) * lengthOfBuffer);

should do it. After that you can write the buffer with memcpy or with an assignation, like you are doing.