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pythondebuggingstack-trace

Print current call stack from a method in code

In Python, how can I print the current call stack from within a method (for debugging purposes).

Solution

  • Here's an example of getting the stack via the traceback module, and printing it:

    import traceback

def f():
    g()

def g():
    for line in traceback.format_stack():
        print(line.strip())

f()

# Prints:
# File "so-stack.py", line 10, in <module>
#     f()
# File "so-stack.py", line 4, in f
#     g()
# File "so-stack.py", line 7, in g
#     for line in traceback.format_stack():

    If you really only want to print the stack to stderr, you can use:

    traceback.print_stack()

    Or to print to stdout (useful if want to keep redirected output together), use:

    traceback.print_stack(file=sys.stdout)

    But getting it via traceback.format_stack() lets you do whatever you like with it.