Socket.receive in python

Question

I made a simple TCP fuzzer in Python. I need it to be able to receive some response and if I didn't get the response, break the loop. My code is this:

import socket
from time import sleep
import sys

ip = raw_input ("please insert host ip: ")
port = input ("please insert port to fuzz: ")
packet = raw_input ("what string would you like to fuzz with? :  ")
multi = input ("in what jumps would you liike to multiply the string ? (10 = A*10) : ")
host = ip, port
s = socket.socket()
char = packet * multi
a = 1

try:
    while a > 0:
        s.connect((host))
        s.send(packet)
        sleep(1) 
        print 'fuzzing param %s' % (packet)
        packet = char + packet 
        s.close()
except (Exception):
    print "Connection lost for some reason"'

But when I run the program I get this error:

please insert host ip: 10.0.0.138
please insert port to fuzz: 80
what string would you like to fuzz with? :  A
in what jumps would you liike to multiply the string ? (10 = A*10) : 2
fuzzing param A
Connection lost

which is weird because it just suppose to reconnect in an endless loop , (i know the server didn't crush)

Answer 1

The remote endpoint simply hung up, probably because the data you send doesn't match the format it expects.

You can either create a new connection every time the remote end hangs up, or send a data in the format that the remote end expects. For example, if the remote end is an HTTP server, you may want to send the request line first, and then the fuzzed part, like this:

GET / HTTP/1.0
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA