WCF REST: What is it expecting my XML to look like in requests?

Question

I have the following method in my WCF service:

[OperationContract]
[WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, RequestFormat = WebMessageFormat.Xml)]
public int GetOne(string param1, string param2)
{
    return 1;
}

I am sending xml from a Flex application, and it takes an object that looks like this: { param1: "test", param2: "test2" } and turns it into the following request:

POST http://localhost:8012/MyService.svc/GetOne HTTP/1.1
Accept: application/xml
Accept-Language: en-US
x-flash-version: 10,1,53,64
Content-Type: application/xml
Content-Length: 52
Accept-Encoding: gzip, deflate
User-Agent: Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; WOW64; Trident/5.0)
Host: localhost:8012
Connection: Keep-Alive
Pragma: no-cache
Cookie: ASP.NET_SessionId=drsynacw0ignepk4ya4pou23

<param1>something</param1><param2>something</param2>

I get the error The incoming message has an unexpected message format 'Raw'. The expected message formats for the operation are 'Xml', 'Json'.. Everything I've read indicates that I just need the content-type to be application/xml, but it still thinks it's Raw for some reason. Given my method signature, I'm confused as to what it's expecting and how I need to form the request so it will accept it as XML.

Am I missing something obvious here? Why does it think it's RAW when it's specifying XML and providing XML?

Edit - Here's the Flex side in case I'm missing something here.

var getOneService:HttpService = new HttpService("myURL");

getOneService.method = "POST";
getOneService.resultFormat = "e4x";
getOneService.contentType = HTTPService.CONTENT_TYPE_XML;
getOneService.headers = { Accept: "application/xml" };

getOneService.send({ param1: "test", param2: "test2" });

Answer 1

I don't think you can pass 2 parameters with a POST operation for the framework to deserialize it automatically. You have try some of the below approaches:

1. Define your WCF method to be as below:

   [OperationContract]
   [WebInvoke(Method = "POST", 
       BodyStyle = WebMessageBodyStyle.Bare, 
       ResponseFormat = WebMessageFormat.Xml, 
       RequestFormat = WebMessageFormat.Xml, 
       URITemplate="/GetOne/{param1}")]
   public int GetOne(string param1, string param2)
   {
       return 1;
   }
   

   Your raw POST request would looks like as below:

   POST http://localhost/SampleService/RestService/ValidateUser/myparam1 HTTP/1.1
   User-Agent: Fiddler
   Content-Type: application/xml
   Host: localhost
   Content-Length: 86
   
   <string xmlns="http://schemas.microsoft.com/2003/10/Serialization/">my param2</string>
   

2. Change your WCF REST method to be as below:

   [OperationContract]
   [WebInvoke(Method = "POST", 
       BodyStyle = WebMessageBodyStyle.WrappedRequest, 
       ResponseFormat = WebMessageFormat.Json, 
       RequestFormat = WebMessageFormat.Json)]
   public int GetOne(string param1, string param2)
   {
       return 1;
   }
   

   Now your raw request should looks something like below:

   POST http://localhost/SampleService/RestService/ValidateUser HTTP/1.1
   User-Agent: Fiddler
   Content-Type: application/json
   Host: localhost
   Content-Length: 86
   
   {"param1":"my param1","param2":"my param 2"}
   

3. Change your WCF REST method to be as below:

   [OperationContract]
   [WebInvoke(Method="POST", 
       BodyStyle=WebMessageBodyStyle.WrappedRequest, 
       ResponseFormat=WebMessageFormat.Xml, 
       RequestFormat= WebMessageFormat.Xml)]
   public int GetOne(string param1, string param2)
   {
      return 1;
   }
   

   Now your raw request would look like something below:

   POST http://localhost/SampleService/RestService/ValidateUser HTTP/1.1
   User-Agent: Fiddler
   Content-Type: application/xml
   Host: localhost
   Content-Length: 116
   
   <ValidateUser xmlns="http://tempuri.org/"><Username>my param1</Username><Password>myparam2</Password></ValidateUser>