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pythonxmppxmpppy

How can I send data using xmpppy?

How can I send data with xmpppy using this method: http://xmpp.org/extensions/xep-0047.html#send

I suppose I should use IBB class but have no idea how to do it. http://xmpppy.sourceforge.net/apidocs/

Solution

  • First, if you're on GoogleTalk, ensure that the sender is on the receiver's roster. Next, on the sender side:

    from xmpp import *
cl=Client('example.com')
cl.connect()
cl.auth('sender', 'sender_pass')
ibb = filetransfer.IBB()
ibb.PlugIn(cl)

f = open('/tmp/foo')
ibb.OpenStream('123', '[email protected]/resource', f)

    It doesn't matter what the stream ID is if you're not doing XEP-95/XEP-96 correctly first.