I want to send a POST request using just a raw string.
I'm writing a parser. I've loaded page and seen such a complicated request with many headers and body in firebug:
__EVENTTARGET=&__EVENTARGUMENT=&__VIEW.... (11Kb or unreadable text)
How can I send this exact request one more time (headers+post body) manually (passing it as a huge string)?
Like:
func("%(headers) \n \n %(body)" % ... )
I want it to be send by my script (and response to be handled) and don't want to make a dictionary of parameters and headers manually.
Thank you.
The other answer just got too big and confusing and was showing more than what you are asking. I felt I should include a more concise answer for future readers to come across:
import urllib2
import urllib
import urlparse
# this was the header and data strings you already had
headers = 'baz=3&foo=1&bar=2'
data = 'baz=3&foo=1&bar=2'
header_dict = dict(urlparse.parse_qsl(headers))
r = urllib2.Request('http://www.foo.com', data, headers)
resp = urllib2.urlopen(r)
You will need to at least parse the headers back into a dict, but its minimal work. Then just pass it all along to a new request.
*Note: This concise example assumes both your headers and your data body are application/x-www-form-urlencoded format. If the headers are in a raw string format like Key: Value, then see the other answer for more detail on parsing that first.
Ultimately, you can't just copy-paste the raw text and run a new request. It has to be divided into header and data in the proper formats.