flag to overwrite download url command

Question

I am pretty new to shell scripting and I have to add a flag (getopts) to my script where I can overwrite download url command if the script can't reach the url for any reason. For instance, if I add my flag then it won't terminate my script, I can choose to continue if url can't be reached.

Currently, I have

if "$?" -ne "0" then
echo "can't reach the url, n\ aborting"
exit

Now I need to add a flag through getopts where I can choose to ignore "$?' - ne "0" command,

I don't know how getopts works, I am pretty new to it. Can someone please help me on how to go about it?

Answer 1

If you only have one option, sometimes it's simpler to just check $1:

# put download command here
if (( $? != 0 )) && [[ $1 != -c ]]; then
    echo -e "can't reach the url, \n aborting"
    exit
fi
# put stuff to do if continuing here

If you're going to accept other options, some possibly with arguments, the getopts should be used:

#!/bin/bash
usage () { echo "Here is how to use this program"; }

cont=false

# g and m require arguments, c and h do not, the initial colon is for silent error handling
options=':cg:hm:' # additional option characters go here
while getopts $options option
do
    case $option in
        c  ) cont=true;;
        g  ) echo "The argument for -g is $OPTARG"; g_option=$OPTARG;; #placeholder example
        h  ) usage; exit;;
        m  ) echo "The argument for -m is $OPTARG"; m_option=$OPTARG;; #placeholder example
        # more option processing can go here
        \? ) echo "Unknown option: -$OPTARG"
        :  ) echo "Missing option argument for -$OPTARG";;
        *  ) echo "Unimplimented option: -$OPTARG";;
    esac
done

shift $(($OPTIND - 1))

# put download command here
if (( $? != 0 )) && ! $cont; then
    echo -e "can't reach the url, \n aborting"
    exit
fi
# put stuff to do if continuing here