dereference and advance pointer in one statement?

Question

I'm reading from a byte array as follows:

int* i = (int*)p;
id = *i;
i++;

correct me if I'm wrong, but ++ has precedence over *, so is possible to combine the *i and i++ in the same statement? (e.g. *i++)

(this is technically unsafe C#, not C++, p is a byte*)

Answer 1

I believe that

id = *i;
i++;

and

id = *i++;

are equivalent.

The ++ operator, when used as a suffix (e.g. i++), returns the value of the variable prior to the increment.

---

I'm somewhat confused by the reflector output for

unsafe class Test
{
    static public void Test1(int p, out int id)
    {
        int* i = (int*)(p);
        id = *i;
        i++;
    }

    static public void Test2(int p, out int id)
    {
        int* i = (int*)(p);
        id = *i++;
    }
}

which comes out as

public static unsafe void Test1(int p, out int id)
{
    int* i = (int*) p;
    id = i[0];
    i++;
}

and

public static unsafe void Test2(int p, out int id)
{
    int* i = (int*) p;
    i++;
    id = i[0];
}

which clearly are not equivalent.