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javainet-socket

What does Java InetSocketAddress look like .toString()?

I'm doing a .toString() on an InetSocketAddress. This is part of an Android websocket client that so far is failing to connect to the host.

Right now the output from a variable address.toString() looks like domain.com/72.xx.xxx.xx:8000 but from what I understand there needs to be two values (IP and port) only?

Thanks letting me know if this looks correct.

Solution

  • The toString() of InetSocketAddress first calls the toString() of InetAddress and then appends the port number to it and the string returned from toString() of InetAddress is of the form: hostname / literal IP address.

    Later port number is concatenated before returning from the InetSocketAddress's toString() to the returned value (from the toString() of InetAddress), hence the final result is hostname / literal IP address:port number.

    For more information see the JavaDocs for InetSocketAddress's toString().