here is my xml file
<TEST>
<Project_Name>browser</Project_Name>
<Setting BrowserKind ="Firefox" ></Setting>
<ExecuteUrl>http://yahoo.com</ExecuteUrl>
<caseBox>
<test1>apple</test1>
</caseBox>
</TEST>
this xml means nothing,it's an example. I just want to make some practice.
here are 3 thing i want to get:
(1)Firefox
(2)http://yahoo.com
(3)apple
I use xmldocument, but failed ,nothing I totally get.
how can I get them???
thanks.
this is my test to get firefox
here is my code:
XmlDocument XmlDoc = new XmlDocument( );
XmlDoc.Load(here I PLACE THE LOCATION OF FILE);
XmlNodeList NodeLists = XmlDoc.SelectNodes("TEST/Setting");
foreach (XmlNode OneNode in NodeLists)
{
String StrAttrValue1 = OneNode.Attributes[" Browserkind "].Value;
String StrAttrValue2 = OneNode.InnerText;
}
If switching to LINQ to XML is an option, rather than the older Xml API, I'd do it.
var doc = XDocument.Parse(@"<TEST>
<Project_Name>browser</Project_Name>
<Setting BrowserKind =""Firefox"" ></Setting>
<ExecuteUrl>http://yahoo.com</ExecuteUrl>
<caseBox>
<test1>apple</test1>
</caseBox>
</TEST>");
var result = (from test in doc.Elements("TEST")
select new { BrowserKind = test.Element("Setting").Attribute("BrowserKind").Value,
ExecuteUrl = test.Element("ExecuteUrl").Value,
CaseBox = test.Element("caseBox").Element("test1").Value });