I have the following:
b = [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double]
whose dimensions are variable.
b{1}
ans =
0 0 0 0
I want to put the first entry of each of the 10 vectors as the first column of matrix A
2nd column of matrix A will be as v the 1st entry of each of the 10 vectors of r:
r =
[1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double] [1x4 double]
r{1} --> ans = 10 10 10 10
This is what i need to get:
A =
v{1}(1) r{1}(1)
v{2}(1) r{2}(1)
v{3}(1) r{3}(1)
How to do that without a loop is there a way?
Some example data:
b = {[ 101:104 ], [ 201:204 ], [ 301:304 ], [ 401:404 ], [ 501:504 ], [ 601:604 ], [ 701:704 ], [ 801:804 ], [ 901:904 ], [ 1001:1004 ]};
r = {[ 2101:2104 ], [ 2201:2204 ], [ 2301:2304 ], [ 2401:2404 ], [ 2501:2504 ], [ 2601:2604 ], [ 2701:2704 ], [ 2801:2804 ], [ 2901:2904 ], [ 3001:3004 ]};
Edit: a lot faster solution without looping by using vertcat.
Edit: corrected a typo in code.
bMatrix = vertcat(b{:});
rMatrix = vertcat(r{:});
A = [ bMatrix(:,1), rMatrix(:,1) ];
A lot slower solution by using cellfun (cellfun does loop) :
A = [ cellfun(@(x) x(1), b)', cellfun(@(x) x(1), r)' ];
Or in parts:
ColumnOneOfMatrixA = cellfun(@(x) x(1), b)';
ColumnTwoOfMatrixA = cellfun(@(x) x(1), r)';
A = [ ColumnOneOfMatrixA, ColumnTwoOfMatrixA ];
Both ways give the same result.
A =
101 2101
201 2201
301 2301
401 2401
501 2501
601 2601
701 2701
801 2801
901 2901
1001 3001