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Check if element is visible in DOM

Is there any way that I can check if an element is visible in pure JS (no jQuery) ?

So, given a DOM element, how can I check if it is visible or not? I tried:

window.getComputedStyle(my_element)['display']);

but it doesn't seem to be working. I wonder which attributes should I check. It comes to my mind:

display !== 'none'
visibility !== 'hidden'

Any others that I might be missing?

Solution

  • According to this MDN documentation, an element's offsetParent property will return null whenever it, or any of its parents, is hidden via the display style property. Just make sure that the element isn't fixed. A script to check this, if you have no position: fixed; elements on your page, might look like:

    // Where el is the DOM element you'd like to test for visibility
function isHidden(el) {
    return (el.offsetParent === null)
}

    On the other hand, if you do have position fixed elements that might get caught in this search, you will sadly (and slowly) have to use window.getComputedStyle(). The function in that case might be:

    // Where el is the DOM element you'd like to test for visibility
function isHidden(el) {
    var style = window.getComputedStyle(el);
    return (style.display === 'none')
}

    Option #2 is probably a little more straightforward since it accounts for more edge cases, but I bet its a good deal slower, too, so if you have to repeat this operation many times, best to probably avoid it.